The intensity of light from a source is left( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The intensity $I$ of an electromagnetic wave is related to the amplitude of the electric field $E_0$ by the formula: $I = \frac{1}{2} \epsilon_0 c

Vedclass · Accepted Answer

$2\sqrt{3} 	imes 10^2 \, N/C$

Vedclass · Answer

(B) The intensity $I$ of an electromagnetic wave is related to the amplitude of the electric field $E_0$ by the formula: $I = \frac{1}{2} \epsilon_0 c E_0^2$.Rearranging for $E_0$,we get: $E_0 = \sqrt{\frac{2I}{\epsilon_0 c}}$.Given: $I = \frac{500}{\pi} \, W/m^2$,$\epsilon_0 = \frac{1}{36\pi 	imes 10^9} \, F/m$,and $c = 3 	imes 10^8 \, m/s$.Substituting the values:$E_0 = \sqrt{\frac{2 	imes (500/\pi)}{(1 / (36\pi 	imes 10^9)) 	imes 3 	imes 10^8}}$$E_0 = \sqrt{\frac{1000}{\pi} 	imes \frac{36\pi 	imes 10^9}{3 	imes 10^8}}$$E_0 = \sqrt{1000 	imes 12 	imes 10} = \sqrt{120000} = \sqrt{12 	imes 10^4} = 2\sqrt{3} 	imes 10^2 \, N/C$.

The intensity of light from a source is $\left( \frac{500}{\pi} \right) \, W/m^2$. Find the amplitude of the electric field in this wave.

Similar Questions

$A$ point source of electromagnetic radiation has an average power output of $800 \ W$. Find the maximum value of the magnetic field at a distance of $3.5 \ m$ from the source.

The magnetic field of an electromagnetic wave is given by $\vec B = 1.6 \times 10^{-6} \cos(2 \times 10^7 z + 6 \times 10^{15} t) (2\hat i + \hat j) \text{ Wb/m}^2$. The associated electric field will be

The frequency of an electromagnetic wave is $25 \ MHz$. If the magnitude of the electric field at a point at any instant is $6.3 \ V/m$,then the magnitude of the magnetic field at that point is ..... $Wb/m^2$.

For which of the following media will the wave propagation occur without experiencing attenuation?

In the propagation of electromagnetic waves,the angle between the direction of propagation and the plane of polarisation is......$^o$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module